1988 United States Senate election in Ohio

The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.[1] As of 2022, this remains the last time that Ohio would support different parties in a concurrent presidential and Senate election.

1988 United States Senate election in Ohio

November 8, 1988
 
Nominee Howard Metzenbaum George Voinovich
Party Democratic Republican
Popular vote 2,480,038 1,872,716
Percentage 57.0% 42.3%

County results
Metzenbaum:      50–60%      60–70%      70–80%
Voinovich:      50-60%      60-70%

U.S. senator before election

Howard Metzenbaum
Democratic

Elected U.S. Senator

Howard Metzenbaum
Democratic

Major candidates

Democratic

Republican

Results

1988 United States Senate election in Ohio
Party Candidate Votes %
Democratic Howard Metzenbaum (incumbent) 2,480,038 56.97%
Republican George Voinovich 1,872,716 42.31%
Independent David Marshall 151 0.00%
Majority 607,322 8.68%
Turnout 4,352,905 100.00%
Democratic hold

See also

References

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