1994 Romanian Open – Doubles

Menno Oosting and Libor Pimek were the defending champions, but competed this year with different partners. Oosting teamed up with Federico Mordegan and lost in the first round to Saša Hiršzon and Goran Ivanišević, while Pimek teamed up with Filip Dewulf and also lost in the first round to Jon Ireland and Jack Waite.

Doubles
1994 Romanian Open
Champions Wayne Arthurs
Simon Youl
Runners-up Jordi Arrese
José Antonio Conde
Final score6–4, 6–4

Wayne Arthurs and Simon Youl won the title by defeating Jordi Arrese and José Antonio Conde 6–4, 6–4 in the final.[1]

Seeds

  1. Federico Mordegan / Menno Oosting (First round)
  2. Tomás Carbonell / Francisco Roig (Quarterfinals)
  3. Neil Broad / Greg Van Emburgh (First round)
  4. Jon Ireland / Jack Waite (Quarterfinals)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 F Mordegan
M Oosting
3 4
WC S Hiršzon
G Ivanišević
6 6 WC S Hiršzon
G Ivanišević
6 1 4
V Flégl
K Kučera
4 2 W Arthurs
S Youl
3 6 6
W Arthurs
S Youl
6 6 W Arthurs
S Youl
6 6
4 J Ireland
J Waite
6 6 M Blackman
R Furlan
4 2
F Dewulf
L Pimek
3 4 4 J Ireland
J Waite
6 6
M Blackman
R Furlan
6 6 M Blackman
R Furlan
7 7
Q P Gauthier
C Gómez-Díaz
3 2 W Arthurs
S Youl
6 6
G Köves
L Markovits
6 6 J Arrese
JA Conde
4 4
WC A Pavel
R Sabău
7 7 WC A Pavel
R Sabău
6 2 6
A Gaudenzi
B Larkham
6 6 A Gaudenzi
B Larkham
4 6 4
3 N Broad
G Van Emburgh
4 4 WC A Pavel
R Sabău
4 6 4
WC G Cosac
CP Porumb
6 3 6 J Arrese
JA Conde
6 4 6
J Arrese
JA Conde
1 6 7 J Arrese
JA Conde
6 7
Ģ Dzelde
B Mota
3 3 2 T Carbonell
F Roig
4 6
2 T Carbonell
F Roig
6 6

References

  1. "ATP Bucharest Doubles 1994 Draw". Tennis 24. Retrieved 29 April 2022.
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