1880 United States presidential election in New Jersey

The 1880 United States presidential election in New Jersey took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

1880 United States presidential election in New Jersey

November 2, 1880
 
Nominee Winfield S. Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William H. English Chester A. Arthur
Electoral vote 9 0
Popular vote 122,565 120,555
Percentage 49.84% 49.02%

County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

New Jersey voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield. Hancock won the state by a very narrow margin of 0.82%.

A Democratic candidate would not win New Jersey while losing the national popular vote again until 2004.

Results

1880 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 122,565 49.84% 9 100.00%
Republican James Abram Garfield of Ohio Chester Alan Arthur of New York 120,555 49.02% 0 0.00%
Greenback James Baird Weaver of Iowa Barzillai Jefferson Chambers of Texas 2,617 1.06% 0 0.00%
Prohibition Neal Dow of Maine Henry Adams Thompson of Ohio 191 0.08% 0 0.00%
Total 245,928 100.00% 9 100.00%

See also

References


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