1986 Virginia Slims of Pennsylvania – Doubles

Mary Lou Piatek and Robin White were the defending champions, but none competed this year.

Doubles
1986 Virginia Slims of Pennsylvania
Champions Candy Reynolds
Anne Smith
Runners-up Sandy Collins
Kim Sands
Final score7–6, 6–1

Candy Reynolds and Anne Smith won the title by defeating Sandy Collins and Kim Sands 7–6, 6–1 in the final.[1]

Seeds

  1. Svetlana Parkhomenko / Larisa Savchenko (quarterfinals, withdrew)
  2. Lori McNeil / Catherine Suire (semifinals)
  3. Candy Reynolds / Anne Smith (champions)
  4. Sandy Collins / Kim Sands (final)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 S Parkhomenko
L Savchenko
7 6
J Richardson
J Thompson
6 4 1 S Parkhomenko
L Savchenko
L Allen
I Budařová
6 6 0 A Betzner
M Schropp
w/o
A Betzner
M Schropp
4 7 6 A Betzner
M Schropp
5 1
4 S Collins
K Sands
6 6 4 S Collins
K Sands
7 6
V Nelson-Dunbar
Carol Watson
3 3 4 S Collins
K Sands
5 7 6
R Blount
A Tobin-Dingwall
6 4 2 A Minter
E Minter
7 6 3
A Minter
E Minter
3 6 6 4 S Collins
K Sands
6 1
H Na
A Villagrán
7 7 3 C Reynolds
A Smith
7 6
H Crowe
K Steinmetz
6 6 H Na
A Villagrán
1 2
B Cordwell
L Field
6 2 3 C Reynolds
A Smith
6 6
3 C Reynolds
A Smith
7 6 3 C Reynolds
A Smith
7 7
C Copeland
T Mochizuki
6 6 2 L McNeil
C Suire
6 5
D Farrell
J Goodling
4 1 C Copeland
T Mochizuki
0 1
S Amiach
H Ludloff
6 4 2 L McNeil
C Suire
6 6
2 L McNeil
C Suire
7 6

References

  1. "Australian Janine Thompson scored her first professional victory". Hershey, Pennsylvania. United Press International. 9 March 1986. Retrieved 8 December 2021. Candy Reynolds of Knoxville, Tenn., and Anne Smith of Dallas defeated Sandy Collins of Odessa, Texas, and Kim Sands of Miami, Fla., 7-6, 6-1, in the doubles championship.
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